When three resistors are connected in series and produce an amperage of ten amps, what will the amperage be if an equal resistor is added in parallel with the existing three?

When resistors are connected in series, they share the same current, meaning that the amperage that flows through each resistor is the same as the total current flowing through the circuit. In the scenario where three resistors in series are producing an amperage of ten amps, the current remains consistent across each of the resistors.

Adding a resistor in parallel with the existing series of resistors changes the overall circuit configuration, but it does not affect the current that flows through the original series connection. In a parallel configuration, the total current supplied from the source divides among the parallel branches, but as long as the series part of the circuit is still present, the current through it remains at ten amps.

In this case, since the question asked specifically about the amperage flowing through the series connection (where the original resistors are), the amperage will still be maintained at ten amps despite the addition of another resistor in parallel. Hence, the answer is that the amperage after adding the equal resistor in parallel stays the same at ten amps.